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姹借潟浣欓噺Δh
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鏌愰洟蹇冩车寰炴ǎ鏈笂鏌ュ緱鍏佽ū鍚镐笂鐪熺┖楂樺害Hs=5.7m銆傚凡鐭ュ惛鍏ョ璺殑鍏ㄩ儴闃诲姏鐐�1.5mH2O锛岀暥?sh霉)鍗閳敖?.81×104Pa锛屾恫楂斿湪鍚稿叆绠¤矾涓殑鍕曞闋彲蹇界暐銆傝│瑷堢畻锛�
鈶犺几閫�20鈩冩竻姘存檪娉电殑瀹夎锛涒憽鏀圭偤杓搁��80鈩冩按鏅傛车鐨勫畨瑁濋珮搴︺��
瑙ｏ細鈶犺几閫�20鈩冩竻姘存檪娉电殑瀹夎楂樺害 宸茬煡锛欻s=5.7m Hf0-1=1.5m銆�u12/2g≈0
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鈶¤几閫�80鈩冩按鏅傛车鐨勫畨瑁濋珮搴�
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宸茬煡Ha=9.81×104Pa≈10mH2O锛岀敱闄勯寗鏌ュ緱80鈩冩按鐨勯＝鍜岃捀姹藉鐐�47.4kPa銆�
Hv=47.4×103 Pa锛�4.83 mH2O Hs1锛�5.7+10锛�10.33锛�4.83+0.24=0.78m
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